444x^2-22=222+444

Solution for 444x^2-22=222+444 equation:

444x^2-22=222+444

We move all terms to the left:

444x^2-22-(222+444)=0

We add all the numbers together, and all the variables

444x^2-22-666=0

We add all the numbers together, and all the variables

444x^2-688=0

a = 444; b = 0; c = -688;
Δ = b2-4ac
Δ = 02-4·444·(-688)
Δ = 1221888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1221888}=\sqrt{256*4773}=\sqrt{256}*\sqrt{4773}=16\sqrt{4773}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{4773}}{2*444}=\frac{0-16\sqrt{4773}}{888}
=-\frac{16\sqrt{4773}}{888}
=-\frac{2\sqrt{4773}}{111}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{4773}}{2*444}=\frac{0+16\sqrt{4773}}{888}
=\frac{16\sqrt{4773}}{888}
=\frac{2\sqrt{4773}}{111}
$